$ For CST=1, the integration points are arranged circumferentially (located at a radius of $ 0.707 times the outside radius of the cross-section. Thus for 4x4 integration, the IP $ are 22.5 degrees apart. For an illustration, use History > Int pt > Etype: beams > Axial stress $ to plot the integration point stresses in the attached example of a cantilever beam in bending. *KEYWORD *control_implicit_general 1,.1 $ use damping for explicit run $*damping_global $,30. *title 9 vs. 16 IP in circular sections $ beam IP output in numerical order (see p. 3.14 in 940 structured user's manual) *interface_springback_lsdyna 5 *set_part 5 1 *CONTROL_TERMINATION 0.9000000 0 0.0000000 0 0.0000000 *DATABASE_BINARY_D3PLOT 0.0100000 0 *DATABASE_EXTENT_BINARY 0 0 0 0 0 0 0 0 0 0 16 0 0 0 *DATABASE_NODOUT 2.00000-3 *DATABASE_HISTORY_BEAM 1,11 *DATABASE_ELOUT 2.00000-3 *DATABASE_SPCFORC 2.00000-3 *DATABASE_BNDOUT 2.00000-3 *MAT_ELASTIC 1 3.00000-4 1.00000+7 0.2000000 $*mat_plastic_kinematic $$1,2e-4,1e7,.2, 20,0,1 $1,2e-4,1e7,.2, 15,1e4,1 $ *SECTION_BEAM 1,1,,3,1 1,1,0,0 $1,1,.5,.5 *SECTION_BEAM 2,1,,4,1 1,1,0,0 $1,1,.5,.5 *PART material type # 1 1 1 1 0 0 0 0 0 *PART material type # 1 2 2 1 0 0 0 0 0 *NODE 1 1.800000000E+01 0.000000000E+00 0.000000000E+00 0 0 2 3.600000000E+01 0.000000000E+00 0.000000000E+00 0 0 3 5.400000000E+01 0.000000000E+00 0.000000000E+00 0 0 4 7.200000000E+01 0.000000000E+00 0.000000000E+00 0 0 5 0.000000000E+00 1.000000000E+00 0.000000000E+00 0 0 11 1.800000000E+01 0.000000000E+00 9.000000000E+00 0 0 12 3.600000000E+01 0.000000000E+00 9.000000000E+00 0 0 13 5.400000000E+01 0.000000000E+00 9.000000000E+00 0 0 14 7.200000000E+01 0.000000000E+00 9.000000000E+00 0 0 15 0.000000000E+00 1.000000000E+00 9.000000000E+00 0 0 *ELEMENT_BEAM 1 1 1 2 5 2 1 2 3 5 3 1 3 4 5 11 2 11 12 15 12 2 12 13 15 13 2 13 14 15 *BOUNDARY_SPC_NODE 1 0 1 1 1 1 1 1 11 0 1 1 1 1 1 1 *DEFINE_CURVE 1 0 0.0000000 2. 0.00000000E+00 0.00000000E+00 5.00000001E-01 1.0 1.00000000E+00 1.0 *LOAD_NODE_POINT 4 2 1 14 2 1 *END